This question was previously asked in

Official Paper 19: Held on 11th Nov 2020 Shift 1

Option 2 : 60 minutes

**Given:**

The man reaches the office late by 30 minutes

**Formula used:**

Distance = Speed × Time

**Concept used:**

Speed is inversely proportional to the time taken

**Calculation:**

Let the distance from the office and home be x and original speed be y

Then, the Original time is taken = x/y

Decreased speed = 2y/3

Time is taken when speed is decreased = Distance/Speed = x/(2y/3)

Now, A/Q

x/(2y/3) – x/y = 30

⇒ 3x/2y – x/y = 30

⇒ x/2y = 30

⇒ x/y = 30 × 2 = 60 minutes

**∴ The actual time is taken by the man to reach the office is 60 minutes**